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square triangular number : ウィキペディア英語版
square triangular number

In mathematics, a square triangular number (or triangular square number) is a number which is both a triangular number and a perfect square.
There are an infinite number of square triangular numbers; the first few are 0, 1, 36, 1225, 41616, 1413721, 48024900, 1631432881, 55420693056, 1882672131025 .
==Explicit formulas==

Write ''N''''k'' for the ''k''th square triangular number, and write ''s''''k'' and ''t''''k'' for the sides of the corresponding square and triangle, so that
:N_k = s_k^2 = \frac.
Define the ''triangular root'' of a triangular number N = \frac to be n. From this definition and the quadratic formula, n = \frac. Therefore, N is triangular if and only if 8N + 1 is square, and naturally N^2 is square and triangular if and only if 8N^2 + 1 is square, i. e., there are numbers x and y such that x^2 - 8y^2 = 1. This is an instance of the Pell equation, with n=8. All Pell equations have the trivial solution (1,0), for any n; this solution is called the zeroth, and indexed as (x_0,y_0). If (x_k,y_k) denotes the k'th non-trivial solution to any Pell equation for a particular n, it can be shown by the method of descent that x_ = 2x_k x_1 - x_ and y_ = 2y_k x_1 - y_. Hence there are an infinity of solutions to any Pell equation for which there is one non-trivial one, which holds whenever n is not a square. The first non-trivial solution when n=8 is easy to find: it is (3,1). A solution (x_k,y_k) to the Pell equation for n=8 yields a square triangular number and its square and triangular roots as follows: s_k = y_k , t_k = \frac, and N_k = y_k^2. Hence, the first square triangular number, derived from (3,1), is 1, and the next, derived from (17,6) (=6×(3,1)-(1,0)), is 36.
The sequences ''N''''k'', ''s''''k'' and ''t''''k'' are the OEIS sequences , , and respectively.
In 1778 Leonhard Euler determined the explicit formula〔
〕〔

:N_k = \left( \frac)^k}
N_k &= \left( ( 1 + \sqrt )^ - ( 1 - \sqrt )^ \right)^2 = \left( ( 1 + \sqrt )^-2 + ( 1 - \sqrt )^ \right) \\
&= \left( ( 17 + 12\sqrt )^k -2 + ( 17 - 12\sqrt )^k \right).
\end
The corresponding explicit formulas for ''s''''k'' and ''t''''k'' are 〔
: s_k = \frac)^k})^k + (3 - 2\sqrt)^k - 2}.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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